e812fbaee0
If there are no terms to filter on, we should return a set of all items. This will show all songs when a space has been entered into the filter bar.
77 lines
1.5 KiB
Python
77 lines
1.5 KiB
Python
# Bryan Schumaker (8/10/2010)
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import re
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translate = unicode.translate
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split = unicode.split
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space_ord = ord(" ")
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stripc = u"\"#$%&'*+<=>@[]^`{|}~.?!"
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splitc = u"-\/,:;()_~+"
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ttable = None
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def format_once(text):
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import string
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global ttable
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upper = string.uppercase
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lower = string.lowercase
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ttable = dict((ord(c),None) for c in stripc)
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splitt = dict((ord(c),space_ord) for c in splitc)
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lowert = dict((ord(c),ord(lower[i])) for i,c in enumerate(upper))
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for t in (splitt, lowert):
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for c in t:
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ttable[c] = t[c]
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format = format_rest
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return format_rest(text)
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def format_rest(text):
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return text.translate(ttable).split()
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format = format_once
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class Index(dict):
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def __init__(self):
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dict.__init__(self)
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def insert(self, id, tags):
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get = self.get
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for tag in tags:
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for word in format(tag):
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ids = get(word, None)
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if ids == None:
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self[word] = set([id])
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else:
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ids.add(id)
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def filter(self, text):
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text = unicode(text)
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terms = format(text)
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results = dict()
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visible = set()
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search = re.search
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get = self.get
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# Return the set of all items if there is nothing to search on
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if len(terms) == 0:
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for key in self.keys():
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visible.update(get(key))
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return visible
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for t in terms:
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results[t] = set()
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for key in self.keys():
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for term in terms:
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if search(term, key):
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results[term].update(get(key))
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for i,t in enumerate(terms):
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if i == 0:
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visible.update(results[t])
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else:
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visible.intersection_update(results[t])
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return visible
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