Update reply handler

What we really want to do is look for the first line beginning with ">"
and discard everything after it (and the line immediately before it,
just to be safe)

Signed-off-by: Anna Schumaker <Anna@OcarinaProject.net>

slackpost.py

@@ -26,12 +26,12 @@ if channel == None:
     sys.exit(1)
 
 lines = headers.get_payload().strip().split("\n")
+for i in range(len(lines)):
+    if len(lines[i]) == 0:
+        continue
+    if lines[i][0] == ">":
+        break
 
-# Strip out quoted text
-if lines[-1][0] == ">":
-    while lines[-1][0] == ">":
-        lines.pop(-1)
-    lines.pop(-1)
-
+lines = lines[0:i-1]
 text = ' '.join(lines).strip()
 channel.post(text)